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x^2-196x=960.4
We move all terms to the left:
x^2-196x-(960.4)=0
We add all the numbers together, and all the variables
x^2-196x-960.4=0
a = 1; b = -196; c = -960.4;
Δ = b2-4ac
Δ = -1962-4·1·(-960.4)
Δ = 42257.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-196)-\sqrt{42257.6}}{2*1}=\frac{196-\sqrt{42257.6}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-196)+\sqrt{42257.6}}{2*1}=\frac{196+\sqrt{42257.6}}{2} $
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